CRC method can detect a single burst of length n, since only one bit per column will be changed, a burst of length n+1 will pass undetected, if the first bit is inverted, the last bit is inverted and all other bits are correct. If the block is badly garbled by a long burst or by multiple shorter burst, the probability that any of the n columns will have the correct parity that is 0.5.
C Programming: I'm writing a program for a CRC 12. As of right now I only need help on my calculation portion. It's a program that takes in two argument values from the command line argv1 is c or v (only foucused on c for now) and the second is argv2 which is any uppercase hex value from 0-9 A-F 3 to 40 characters long.
So the probability of a bad block being expected when it should not be 2 power(-n). This scheme sometimes is known as Cyclic Redundancy Code.
Algorithm Steps:Step 1: Declare int crc 16, SHIFTCRC, shift Byte, ByteSIZE as global variables.Step 2: Input the data in a file.Step 3: perform the crc computation using cal CRC 16.Step 4: In cal CRC 16 each character from input shifted with shift-byte where value 987.Step 5: Output of step 4 and step 5 are exclusive.Step 6: store in a temporary variable.Step 7: Byte value is now leftshifted by 1.Step 8: The loop is repeated for the Bytesize.Step 9: The computed crc is display as output in screen.
Comments are closed.
|
AuthorWrite something about yourself. No need to be fancy, just an overview. Archives
March 2023
Categories |